Given a positive integer, return its corresponding column title as appear in an Excel sheet.

For example:

    1 -> A
    2 -> B
    3 -> C
    ...
    26 -> Z
    27 -> AA
    28 -> AB 

Credits:
Special thanks to @ifanchu for adding this problem and creating all test cases.

算法分析: 一眼就能看出来这是一个10进制转化为26进制的算法了.
顺便贴上各个语言版本的运行效率.

Java:

public class Solution {
    public String convertToTitle(int n) {
        char c = '0';
        int mod = 0;
        String str = "";
        while(n > 0) {
            mod = n % 26;
            n = n / 26;
            if (mod == 0) {
                c = 'Z';
                n--;
            }
            else
                c = (char)(mod - 1 + (int)'A');
            str = c + str;
        }
        return str;
    }
}

C++:

class Solution {
public:
    string convertToTitle(int n) {
        char c = '0';
        string str = "";
        int mod = 0;
        while (n > 0) {
            mod = n % 26;
            n /= 26;
            if (mod == 0) {
                c = 'Z';
                n--;
            } else 
                c = mod - 1 + 'A';
                
            str = c + str;
        }
        return str;
    }
};

Python:

class Solution:
    # @return a string
    def convertToTitle(self, num):
        c = ''
        str = ''
        mod = 0
        while (num > 0):
            mod = num % 26
            num /= 26
            if (mod == 0):
                num = num - 1
                c = 'Z'
            else:
                c = (chr)(ord('A') + mod - 1)
            str = c + str
        return str

本博客所有文章如无特别注明均为原创。作者：Gcaufy
复制或转载请以超链接形式注明转自码疯窝，原文地址 LeetCode 每日一题 — Excel Sheet Column Title